(B+2)(-B^2+4b-3)=

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Solution for (B+2)(-B^2+4b-3)= equation: 


Simplifying
(B + 2)(-1B2 + 4b + -3) = 0

Reorder the terms:
(2 + B)(-1B2 + 4b + -3) = 0

Reorder the terms:
(2 + B)(-3 + -1B2 + 4b) = 0

Multiply (2 + B) * (-3 + -1B2 + 4b)
(2(-3 + -1B2 + 4b) + B(-3 + -1B2 + 4b)) = 0
((-3 * 2 + -1B2 * 2 + 4b * 2) + B(-3 + -1B2 + 4b)) = 0
((-6 + -2B2 + 8b) + B(-3 + -1B2 + 4b)) = 0
(-6 + -2B2 + 8b + (-3 * B + -1B2 * B + 4b * B)) = 0
(-6 + -2B2 + 8b + (-3B + -1B3 + 4bB)) = 0

Reorder the terms:
(-6 + -3B + -2B2 + -1B3 + 8b + 4bB) = 0
(-6 + -3B + -2B2 + -1B3 + 8b + 4bB) = 0

Solving
-6 + -3B + -2B2 + -1B3 + 8b + 4bB = 0

Solving for variable 'B'.

The solution to this equation could not be determined.

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